What amount of copper (2) sulfate is formed if 16.8 g of copper (2) oxide has reacted with sulfuric acid?

1. Let’s compose a chemical equation, not forgetting to put down the coefficients:

CuO + H2SO4 = CuSO4 + H2O.

2. Find the amount of copper oxide substance:

n (CuO) = m / M = 16.8g / 80 g / mol = 0.21 mol.

3. The equation shows that the amount of copper oxide is equal to the amount of copper sulfate:

n (CuO) = n (CuSO4) = 0.21 mol.

Answer: n (CuSO4) = 0.21 mol.

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