What amount of copper sulfate (2) is formed if 16.8 g of chalk oxide (2) reacted with sulfuric acid?

Find the amount of copper oxide substance CuO by the formula:

n = m: M.

M (CuO) = 80 g / mol.

n = 16.8 g: 80 g / mol = 0.21 mol.

Let’s find the quantitative ratios of substances.

СuO + H2SO4 → СuSO4 + H2O

For 1 mol of СuO, there is 1 mol of the СuSO4 salt.

Substances are in quantitative ratios 1: 1.

The amount of substance will be equal.

n (CuSO4) = n (CuO) = 0.21 mol.

Answer: 0.21 mol.