What amount of heat is released in 20 minutes in a conductor with a resistance of 200 Ohms at a current of 0.4 A.

Initial data: t (current passage time) = 20 min; R (conductor resistance) = 200 ohms; I (current strength) = 0.4 A.

SI system: t = 20 min = 20 * 60 = 1200 s.

The amount of heat that is released on the conductor in 20 minutes is determined by the Joule-Lenz law: Q = I ^ 2 * R * t.

Let’s calculate: Q = 0.4 ^ 2 * 200 * 1200 = 38 400 J or 38.4 kJ.

Answer: In 20 minutes, 38.4 kJ of heat is released on the conductor.