What amount of heat is released when 0.1 kg of water cools from 26 ° C to 6 ° C? Specific heat capacity of water 4200 J / (kg K)?
March 30, 2021
The amount of heat is determined from the following expression:
Q = c * m * (t2-t1)
Substitute the numerical values:
Q = c * m * (t2-t1) = 4200 * 0.1 * (26-6) = 8400 J.
Answer: 8,400 J.
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