What amount of heat is released when 0.2 kg of water cools down by 2 K? Specific heat capacity of water 4200 J / (kg K)?

The amount of heat is determined from the following expression:
Q = c * m * (t2-t1)
Substitute the numerical values:
Q = c * m * (t2-t1) = 4200 * 0.2 * 2 = 1680 J.
Answer: 1680 J.

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