What are the volumes of gases obtained during the combustion of hydrogen sulfide in 0.3 mol of oxygen?

Oxidation of hydrogen sulfide with oxygen proceeds in accordance with the following chemical equation:

H2S + 3/2 O2 = H2O + SO2;

When hydrogen sulfide is burned in 0.3 mol of oxygen, 0.3 / (3/2) = 0.2 mol of water vapor and the same amount of sulfur dioxide will be obtained. The total amount of the substance will be 0.2 + 0.2 = 0.4 mol.

Let’s calculate the volume of substances. To do this, multiply the molar amount of the substance by the volume of 1 mole of gas (filling 22.4 liters).

V = 0.4 x 22.4 = 8.96 liters;

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