Oxidation of hydrogen sulfide with oxygen proceeds in accordance with the following chemical equation:
H2S + 3/2 O2 = H2O + SO2;
When hydrogen sulfide is burned in 0.3 mol of oxygen, 0.3 / (3/2) = 0.2 mol of water vapor and the same amount of sulfur dioxide will be obtained. The total amount of the substance will be 0.2 + 0.2 = 0.4 mol.
Let’s calculate the volume of substances. To do this, multiply the molar amount of the substance by the volume of 1 mole of gas (filling 22.4 liters).
V = 0.4 x 22.4 = 8.96 liters;
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