What element is formed from U 238 92 after two alpha decays?

In the process of alpha decay, an alpha particle is separated from the atomic nucleus, which is the nucleus of the helium 4 2He atom.

Nuclear reaction equations:

23892U  = 23490Th + 42He;

23490Th = 23088Ra + 42He;

Answer: with a two-fold alpha decay of the uranium nucleus, radium will be formed.

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