What energy is required to melt scrap iron weighing 100 kg and having a temperature of 10 ° C?

m = 100 kg.

t1 = 10 ° C.

t2 = 1539 ° C.

C = 460 J / kg * ° C.

q = 2.7 * 10 ^ 5 J / kg.

Q -?

In order for iron to pass from a solid state of aggregation to a liquid, it must first be heated to the melting temperature, which is t2 = 1539 ° C, and melted at this temperature. Therefore, the required amount of heat Q will be the sum: Q = Q1 + Q2, where Q1 is the amount of heat required for heating, Q2 is the amount of heat required for melting itself.

Q1 = C * m * (t2 – t1).

Q1 = 460 J / kg * ° С * 100 kg * (1539 ° С – 10 ° С) = 70334000 J.

Q2 = q * m.

Q2 = 2.7 * 10 ^ 5 J / kg * 100 kg = 27,000,000 J.

Q = 70334000 J + 27000000 J = 97334000 J.

Answer: to melt scrap iron you need Q = 97334000 J of thermal energy. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.