m = 100 kg.
t1 = 10 ° C.
t2 = 1539 ° C.
C = 460 J / kg * ° C.
q = 2.7 * 10 ^ 5 J / kg.
In order for iron to pass from a solid state of aggregation to a liquid, it must first be heated to the melting temperature, which is t2 = 1539 ° C, and melted at this temperature. Therefore, the required amount of heat Q will be the sum: Q = Q1 + Q2, where Q1 is the amount of heat required for heating, Q2 is the amount of heat required for melting itself.
Q1 = C * m * (t2 – t1).
Q1 = 460 J / kg * ° С * 100 kg * (1539 ° С – 10 ° С) = 70334000 J.
Q2 = q * m.
Q2 = 2.7 * 10 ^ 5 J / kg * 100 kg = 27,000,000 J.
Q = 70334000 J + 27000000 J = 97334000 J.
Answer: to melt scrap iron you need Q = 97334000 J of thermal energy.
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