What force must be applied to the spring to lengthen it by 12 mm if its stiffness is 1000 N / m?
| August 27, 2021 | education
Initial data: Δх (required elongation of the taken spring) = 12 mm (12 * 10-3 m); k (value of spring stiffness) = 1000 N / m.
The force that must be applied to the taken spring is calculated by the formula: F = -Fcont. = k * Δх.
Calculation: F = 1000 * 12 * 10-3 = 12 N.
Answer: A tensile force of 12 N must be applied to the spring.
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