What is the area of a rectangle ABCD if its sides are 5: 7 and one side is 3 cm larger than the other?

1. If one side of a rectangle refers to the other as 5 to 7, then there are 12 parts in the dimension of its sides and 5 parts are width, and 7 is length. That is, the length is greater than the width by:

7 – 5 = 2 (parts).

2. It is also known that the length is 3 cm greater than the width. Now we can calculate what 1 part will be equal to:

3/2 = 1.5 (cm).

3. Next, find the width of the rectangle:

1.5 x 5 = 7.5 (cm).

4. Now you can calculate the length:

1.5 x 7 = 10.5 (cm).

5. It remains to calculate the area of the rectangle:

10.5 x 7.5 = 78.75 (cm²).

Answer: the area of the AVSD rectangle is 78.75 cm²,