What is the area of a rectangle if its length is 8 dm, and its width is 2 times less?

1. The area of a rectangle can be found by the formula:

S = a * b, where “S” is the area of the rectangle, “a” is the length of the rectangle, and “b” is its width.

2. Knowing that the width is 2 times less than the length, and the length is 8 dm, we find the width:

8/2 = 4 (dm).

3. Find the area of the rectangle:

S = 8 * 4 = 32 (dm ^ 2).

Answer: the area of the rectangle is 32 dm ^ 2



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