What is the area of triangle ABC, if the length of the side AC is 3 cm, and the length of the side AB is 4 cm?

Since the triangle is rectangular, it has two legs: AB = 3 cm and AC = 4 cm and the hypotenuse BC. The area of such a triangle is calculated simply:

S = (AB * AC) / 2,

S = (3 * 4) / 2 = 12/2 = 6 cm2 – the area of this right-angled triangle ABC.

Answer: S = 6 cm2.

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