What is the buoyancy force acting on a 1m3 stone at the bottom of the reservoir?

The buoyancy force of Archimedes will act on the stone in the water, equal to:
Fa = ρ * g * V, where ρ is the density of water (ρ = 1000 kg / m ^ 3), g is the acceleration of gravity (we take g = 9.8 m / s ^ 2), V is the volume of the submerged part of the stone ( V = 1 m ^ 3).
Let’s calculate the buoyancy force of Archimedes:
Fa = ρ * g * V = 1000 * 9.8 * 1 = 9800 N = 9.8 kN.
Answer: The buoyancy force of Archimedes is 9.8 kN.

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