What is the capacity of a capacitor if, when charged to a voltage of 1.4 kV, it receives a charge of 28 nC?

The capacitance of a capacitor can be calculated using the formula:
C = q / U, where C is the capacitance of the capacitor (F), q is the electric charge that the capacitor received (q = 28 nC = 28 * 10 ^ -9 C), U is the voltage across the capacitor plates (U = 1.4 kV = 1.4 * 10 ^ 3 V).
Let’s calculate the capacitance of the capacitor:
C = q / U = (28 * 10 ^ -9) / (1.4 * 10 ^ 3) = 20 * 10 ^ -12 Ф = 20 pF.
Answer: The capacitance of the capacitor is 20 pF.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.