# What is the centripetal acceleration of the end of the minute hand if its length is 2 cm?

December 29, 2020 | education

| Turnover period of the minute hand (T):

T = 60sec

Centripetal acceleration a = V ^ 2 / r

V when moving in a circle:

V = 2pi * r * nu

Let’s substitute:

a = 4 * pi * pi * r / T ^ 2 = 0.0002m / s ^ 2

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