What is the chemical amount of acetic acid required for the complete dissolution of 3.6 g of magnesium?

The reaction equation for the dissolution of magnesium in acetic acid:

Mg + 2CH3COOH = (CH3COO) 2Mg + H2

The amount of Mg substance:

v (Mg) = m (Mg) / M (Mg) = 3.6 / 24 = 0.15 (mol).

According to the reaction equation, 1 mol of Mg reacts with 2 mol of CH3COOH, so the required amount of acetic acid is:

v (CH3COOH) = v (Mg) * 2 = 0.15 * 2 = 0.3 (mol).

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