The reaction equation for the dissolution of magnesium in acetic acid:
Mg + 2CH3COOH = (CH3COO) 2Mg + H2
The amount of Mg substance:
v (Mg) = m (Mg) / M (Mg) = 3.6 / 24 = 0.15 (mol).
According to the reaction equation, 1 mol of Mg reacts with 2 mol of CH3COOH, so the required amount of acetic acid is:
v (CH3COOH) = v (Mg) * 2 = 0.15 * 2 = 0.3 (mol).
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