What is the efficiency of an inclined plane if a load weighing 100 kg is pulled to a height of 2 m, applying a force of 800 N to it? The length of the inclined plane is 4 m.
To calculate the value of the efficiency of the indicated inclined plane, we use the formula: η = Apol / Azatr = m * g * h / (F * l).
Constants and variables: m is the mass of the removed load (m = 100 kg); – acceleration of gravity (g ≈ 10 m / s2); h is the height of pulling out the load (h = 2 m); F – applied force (F = 800 N); l is the length of the indicated inclined plane (l = 4 m).
Calculation: η = m * g * h / (F * l) = 100 * 10 * 2 / (800 * 4) = 0.625 (62.5%).
Answer: The efficiency of the indicated inclined plane is 62.5%.
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