What is the energy of the magnetic field of an electromagnet if at a current of 10 A its inductance is 300 H?

Data: I (current in the indicated electromagnet) = 10 A; I (inductance) = 300 H.

The energy of the magnetic field of the indicated electromagnet: W = L * I ^ 2/2 = 300 * 10 ^ 2/2 = 15 * 10 ^ 3 J.

Answer: The magnetic field of this electromagnet has an energy of 15 kJ.

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