What is the energy of the oscillatory circuit if the maximum charge on the capacitor is 5.5 μC, and the capacitance of the capacitor is 2 μF.
Q = 5.5 μC = 5.5 * 10 ^ -6 C.
C = 2 μF = 2 * 10 ^ -6 F.
The energy of the oscillatory circuit W is determined by the formula: W = Q ^ 2/2 * C.
W = (5.5 * 10 ^ -6 C) ^ 2/2 * 2 * 10 ^ -6 Ф = 7.56 * 10 ^ -6 J.
Answer: the energy of the oscillatory circuit W = 7.56 * 10 ^ -6 J.
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