What is the impulse of a projectile weighing 15 kg at the initial moment of time

What is the impulse of a projectile weighing 15 kg at the initial moment of time if it is fired at an angle of 300 to the horizon at a speed of 60 m / s?

m = 15 kg.

V = 60 m / s.

∠α = 30 °.

P -?

The momentum of the body P is called a vector physical quantity, which is equal to the product of the mass of the body m by the speed of its movement V: P = m * V. The momentum P is directed in the same way as the speed of movement of the body V.

P = 15 kg * 60 m / s = 900 kg * m / s.

Answer: when fired, the projectile has an impulse of P = 900 kg * m / s.