What is the length of the inclined plane if a force of 5 N was applied when moving a load of 1 kg? The height of the inclined plane is 0.2 m, and the efficiency is 80%?
Useful work Wp is expressed in the fact that the load was lifted to a height h: Wp = mgh, where m is the mass of the load, g is the acceleration of gravity.
The work Ww = FL was performed, where F is the force with which the load was pulled, L is the length of the inclined plane.
Efficiency: k = Wp / Ww;
k = mgh / FL;
kFL = mgh;
L = mgh / kF;
L = (1kg * 10 m / s ^ 2 * 0.2 m) / (0.8 * 5 N) = 0.5 m.
Answer: 0.5 m.
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