What is the mass of a load suspended on a spring, if the period of its oscillations is 0.1 s

What is the mass of a load suspended on a spring, if the period of its oscillations is 0.1 s, and the stiffness of the spring is 50n / m?

To find out the mass of the specified load, we use the formula: T = 2 * Π * √ (mg / k), from where we can express: mg / k = T ^ 2 / (4 * Π ^ 2) and mg = k * T ^ 2 / (4 * Π ^ 2).

Data: k – spring rate (k = 50 N / m); T is the period of oscillation of the specified load (T = 0.1 s).

Let’s make a calculation: mg = k * T ^ 2 / (4 * Π ^ 2) = 50 * 0.1 ^ 2 / (4 * 3.14 ^ 2) ≈ 12.68 * 10 ^ -3 kg or 12.68 G.

Answer: The specified load must have a mass of 12.68 g.