What is the mass of aluminum, which will react with potassium hydroxide, if 6.72 liters of gas are released.

Given:
V (gas) = 6.72 l

To find:
m (Al) -?

1) 2Al + 6KOH => 2K3AlO3 + 3H2 ↑;
2) n (H2) = V / Vm = 6.72 / 22.4 = 0.3 mol;
3) n (Al) = n (H2) * 2/3 = 0.3 * 2/3 = 0.2 mol;
4) m (Al) = n * M = 0.2 * 27 = 5.4 g.

Answer: The mass of Al is 5.4 g.



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