What is the mass of calcium reacted with water if 4.44 g of calcium hydroxide were formed?

The equation for the reaction of calcium with water:

Ca + 2H2O = Ca (OH) 2 + H2

Amount of calcium hydroxide substance:

v (Ca (OH) 2) = m (Ca (OH) 2) / M (Ca (OH) 2) = 4.44 / 74 = 0.06 (mol).

According to the reaction equation, 1 mol of Ca (OH) 2 is formed from 1 mol of Ca, therefore:

v (Ca) = v (Ca (OH) 2) = 0.06 (mol).

Thus, the mass of calcium reacted with water:

m (Ca) = v (Ca) * M (Ca) = 0.06 * 40 = 2.4 (g).



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