What is the mass of sulfur that reacted with oxygen if 0.1 mol of sulfur (IV) oxide was formed?


n (SO2) = 0.1 mol,

m (S) -?


S + O2 = SO2

For 1 mol of SO2, there is 1 mol of S.

Substances are in quantitative ratios 1: 1.

The amount of substance is equal.

n (SO2) = n (S) = 0.1 mol.

m = n × M.

M (S) = 32 g / mol.

m = 32 g / mol × 0.1 mol = 3.2 g.

Answer: 3.2 g.

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