What is the mass of sulfur that reacted with oxygen if 0.1 mol of sulfur (IV) oxide was formed?
September 30, 2021 | education
| Given:
n (SO2) = 0.1 mol,
m (S) -?
Solution:
S + O2 = SO2
For 1 mol of SO2, there is 1 mol of S.
Substances are in quantitative ratios 1: 1.
The amount of substance is equal.
n (SO2) = n (S) = 0.1 mol.
m = n × M.
M (S) = 32 g / mol.
m = 32 g / mol × 0.1 mol = 3.2 g.
Answer: 3.2 g.
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