What is the mass of water that can be heated from 20 to 100 degrees, transferring to it all the energy released during the complete combustion of 1 kg of coal?
Initial data: t0 (initial water temperature) = 20 ºС; t (final water temperature) = 100 ºС; m2 (mass of coal consumed) = 1 kg.
Reference values: C (specific heat capacity of water) = 4200 J / (kg * K); q (specific heat of combustion of coal) = 27 MJ / kg = 27 * 10 ^ 6 J / kg.
Since all the energy is transferred to water heating, the equality is true:
Q1 = Q2: С * m1 * (t – t0) = q * m2.
m1 = q * m2 / (С * (t – t0)).
Let’s do the calculation:
m1 = 27 * 10 ^ 6 * 1 / (4200 * (100 – 20)) = 80.36 kg.
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