# What is the minimum work that needs to be done in order to flip a homogeneous

**What is the minimum work that needs to be done in order to flip a homogeneous cube with a mass of 50kg and an edge of 2m to the other side?**

To find the value of the minimum work for flipping a homogeneous cube to an adjacent face, we use the formula (the center of mass of the cube, under the action of the applied force, move from the initial position to the maximum height (the cube will be on the edge), then the cube will descend to the other face under the action of gravity): A = ΔЕп = m * g * (hк – hн) = m * g * (l * √2 / 2 – l / 2).

Constants and variables: m – cube mass (m = 50 kg); g – acceleration due to gravity (g ≈ 9.8 m / s2); l – rib length (l = 2 m).

Calculation: A = m * g * (l * √2 / 2 – l / 2) = 50 * 9.8 * (2 * √2 / 2 – 2/2) = 203 J ≈ 0.2 kJ.

Answer: B) The required minimum work is 0.2 kJ.