What is the molarity of a solution in 200 ml of which contains 25 g of naoh?

In order to calculate the molarity of the solution, we calculate the amount of substance in the available mass of alkali.

To do this, we find the ratio of the weight of the substance to the weight of one mole.

Its molar weight will be:

M NaOH = 23 + 16 + 1 = 40 grams / mol;

The amount of the substance will be:

N NaOH = 25/40 = 0.625 mol;

Let’s calculate the molarity of the solution.

200 ml contains 0.625 mol of base. One liter of such a solution contains 0.625 x 1000/200 = 3.125 mol of base. The solution has a molarity of 3.125 M.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.