v1 = 2 Hz = 2 s ^ -1 = oscillation frequency of the pendulum in the first case;
v2 = 20 Hz = 20 s ^ -1 = frequency of oscillation of the pendulum in the second case.
It is required to determine T1 and T2 (second) – the oscillation period of the spring pendulum in both cases.
The period and frequency of oscillations are related to each other by the formula:
v = 1 / T, hence T = 1 / v.
Then, for the first case:
T1 = 1 / v1 = 1/2 = 0.5 seconds.
For the second case:
T2 = 1 / v2 = 1/20 = 0.05 seconds.
Answer: at a frequency of 2 Hz, the period is 0.5 seconds, at a frequency of 20 Hz, the oscillation period is 0.05 seconds.
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