What is the period of oscillation of a spring pendulum if the oscillation frequency is 2 Hz? 20 Hz?

Given:

v1 = 2 Hz = 2 s ^ -1 = oscillation frequency of the pendulum in the first case;

v2 = 20 Hz = 20 s ^ -1 = frequency of oscillation of the pendulum in the second case.

It is required to determine T1 and T2 (second) – the oscillation period of the spring pendulum in both cases.

The period and frequency of oscillations are related to each other by the formula:

v = 1 / T, hence T = 1 / v.

Then, for the first case:

T1 = 1 / v1 = 1/2 = 0.5 seconds.

For the second case:

T2 = 1 / v2 = 1/20 = 0.05 seconds.

Answer: at a frequency of 2 Hz, the period is 0.5 seconds, at a frequency of 20 Hz, the oscillation period is 0.05 seconds.