What is the period of revolution of a body along a circle with a radius of 20 cm, if the centripetal acceleration is 0.88 m / s?
July 28, 2021 | education|
The period of revolution of the body is calculated from the following formula:
аn = 4Π ^ 2 * R / Т2, where, according to the condition of the problem, аn (centripetal acceleration) = 0.88 m / s2, R (radius of the circle) = 20 cm = 0.2 m.
T2 = 4Π ^ 2 * R / an.
T = √ (4Π ^ 2 * R / an).
Let’s do the calculation:
T = √ (4 * 3.14 ^ 2 * 0.2 / 0.88) = 3 s.
Answer: The period of rotation of this body is 3 s.
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