What is the power of the elevator motor if it evenly lifts 3 tons of ore from a mine 300 m deep in 1.5 minutes? Acceleration modulus of free falling is taken equal to 10 m / s ^ 2
To find the value of the engine power of the specified mine hoist, we apply the formula: N = A / t = m * g * h / t.
Values of variables and constants: m – mass of the raised ore (m = 3 t = 3 * 10 ^ 3 kg); g – acceleration of gravity (by condition we take g = 10 m / s2); h is the depth of the mine (h = 300 m); t – the duration of the rise of the ore (t = 1.5 min = 90 s).
Calculation: N = m * g * h / t = 3 * 10 ^ 3 * 10 * 300/90 = 100 * 10 ^ 3 W = 100 kW.
Answer: The engine power of the specified mine hoist is 100 kW.
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