What is the pulse of a photon whose frequency is 800 * 10 ^ 12 Hz?

The momentum of a photon is determined by the expression:
P = c * m
Einstein’s equation and quantum energy:
E = m * c² = h * ν, where m is the mass of a particle, c is the speed of light, h is Planck’s constant h = 6.63 * 10 ^ -34 J * c, ν is the radiation frequency.
Let us express the mass of a particle from this equality:
m = h * ν / c²
Let’s substitute this into the expression for determining the photon momentum:
P = c * m = c * h * ν / c² = h * ν / c
Substitute the numerical values and determine the photon momentum:
P = h * ν / c = (6.63 * 10 ^ -34) * (800 * 10 ^ 12) / (3 * 10 ^ 8) = 1.76 * 10 ^ -27 kg * m / s.
Answer: the impulse of a photon is 1.76 * 10 ^ -27 kg * m / s.