What is the strength of the current flowing through two series-connected resistors, if in the first of them it is equal to 1A?
These tasks: the considered resistors are connected in series; I1 (current in the first resistor) = 1 A.
Since the resistors in question were connected in series, the equality will be true for them: I = I1 = I2. Therefore, the current flowing through the resistors under consideration is 1 A.
Answer: the current strength is 1 A.
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