What is the volume fraction of oxygen and nitrogen contained in a mixture consisting of 23

What is the volume fraction of oxygen and nitrogen contained in a mixture consisting of 23 liters of nitrogen, 16 liters of oxygen and 46 liters of chlorine.

To find the volume fraction of gas in a mixture, you need to divide the volume of gas by the volume of the mixture, expressed as a percentage.

φ (gas) = V (gas): V (mixture) × 100%.

Find the volume of the mixture. The volume of the mixture is equal to the sum of the volumes of nitrogen, oxygen and chlorine.

V (mixture) = V (N2) + V (O2) + V (Cl2);

V (mixture) = 23 l + 16 l + 46 l = 85 l.

Let’s calculate the volume fraction of oxygen by dividing the volume of oxygen by the volume of the mixture.

φ (O2) = (16 L: 85 L) × 100% = 18.82%.

Let’s calculate the volume fraction of nitrogen.

φ (N2) = (23 L: 85 L) × 100% = 27%.

Answer: φ (O2) = 18.82%; φ (N2) = 27%.




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