What is the volume of a metal ball if it is pushed out of water with a force of 500H?

The force that pushes the metal ball out of the water is the force of Archimedes.

Fa = ρ * g * V, where Fа is the value of the Archimedes force (Fа = 500 N), ρv is the density of water (ρ = 1000 kg / m³), g is the acceleration of gravity (we take g = 10 m / s2), V – the volume of the part of the ball immersed in water (the ball is completely submerged in water).

Let’s calculate the volume of a metal ball:

V = Fa / (ρ * g) = 500 / (1000 * 10) = 0.05 m3.

Answer: The volume of the metal ball is 0.05 m3.