# What is the volume of carbon dioxide released during the thermal decomposition of magnesium carbonate

What is the volume of carbon dioxide released during the thermal decomposition of magnesium carbonate if 10 g of magnesium oxide was obtained?

The decomposition reaction of magnesium carbonate is described by the following chemical reaction equation.

MgCO3 = MgO + CO2;

One mole of magnesium carbonate forms one mole of magnesium oxide and one mole of carbon dioxide.

Let’s find the amount of a substance that is contained in 10 grams of magnesium oxide.

Its molar mass is:

M MgO = 24 + 16 = 40 grams / mol;

The amount of the substance will be equal.

N MgO = 10/40 = 0.25 mol;

The same amount of carbon dioxide will be produced.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Let’s determine the volume of carbon dioxide.

V CO2 = 0.25 x 22.4 = 5.6 liters;

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.