# What is the volume of carbon dioxide released during the thermal decomposition of magnesium carbonate

**What is the volume of carbon dioxide released during the thermal decomposition of magnesium carbonate if 10 g of magnesium oxide was obtained?**

The decomposition reaction of magnesium carbonate is described by the following chemical reaction equation.

MgCO3 = MgO + CO2;

One mole of magnesium carbonate forms one mole of magnesium oxide and one mole of carbon dioxide.

Let’s find the amount of a substance that is contained in 10 grams of magnesium oxide.

Its molar mass is:

M MgO = 24 + 16 = 40 grams / mol;

The amount of the substance will be equal.

N MgO = 10/40 = 0.25 mol;

The same amount of carbon dioxide will be produced.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Let’s determine the volume of carbon dioxide.

V CO2 = 0.25 x 22.4 = 5.6 liters;