What is the volume of carbon monoxide (4) formed when 2 mol of ethane is burned?

The ethane oxidation reaction is described by the following chemical reaction equation.

2C2H6 + 7O2 = 4CO2 + 6H2O;

According to the coefficients of this equation, 7 oxygen molecules are required to oxidize 2 ethane molecules. In this case, 4 molecules of carbon dioxide are synthesized.

There are 2 moles of ethane.

The amount of carbon dioxide will be.

N CO2 = N C2H6 x 2 = 2 x 2 = 4 mol;

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V CO2 = 4 x 22.4 = 89.6 liters;