What is the volume of hydrogen sulfide, which is formed by the interaction of hydrogen with sulfur, if the mass of sulfur is 16 g?
Let’s write the reaction equation:
H2 + S (t) = H2S
Let’s find the amount of sulfur substance:
v (S) = m (S) / M (S) = 16/32 = 0.5 (mol).
According to the reaction equation, 1 mol of H2S is formed from 1 mol of S, therefore:
v (H2S) = v (S) = 0.5 (mol).
Thus, the volume of the formed hydrogen sulfide, measured under normal conditions (n.a.):
V (H2S) = v (H2S) * Vm = 0.5 * 22.4 = 11.2 (l).
Answer: 11.2 l.
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