What is the volume of nitrogen in a vessel under a pressure of 2 * 10 ^ 5 Pa at a temperature of 30 degrees C.
September 13, 2021 | education
| What is the volume of nitrogen in a vessel under a pressure of 2 * 10 ^ 5 Pa at a temperature of 30 degrees C. The mass of nitrogen is 4.5 * 10 ^ -3 kg. The molar mass is 0.028 kg / mol?
Given:
m = 4.5 * 10 ^ -3 kg is the mass of nitrogen;
M = 0.028 kg / mol is the molar mass of nitrogen;
P = 2 * 10 ^ 5 Pa – nitrogen pressure;
T = 30 degrees Celsius = 303 degrees Kelvin – nitrogen temperature.
R = 8.31 J / mol * K – gas constant.
It is required to determine the volume V (m ^ 3) occupied by nitrogen.
According to the Cliperon-Mendeleev law:
V = m * R * T / (M * P) = 4.5 * 10 ^ -3 * 8.31 * 303 / (0.028 * 2 * 10 ^ 5) =
= 11.3 / 5600 = 0.002 m ^ 3 or 2 liters.
Answer: nitrogen occupies a volume equal to 0.002 m ^ 3 (2 liters).
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