Formula of sulfur oxide (VI) SO3. First, you need to find the amount (mol) of the oxide substance: n = m / M, where M is the molar mass in g / mol, m is the mass in g. To do this, we determine the molar mass according to the periodic table: M = 32 + 16 * 3 = 80 g / mol. n (SO3) = 800 g / 80 g / mol = 10 mol. We find the volume by the formula: V = n * Vm, where Vm is the molar volume equal to 22.4 l / mol under normal conditions for all gases. V (SO3) = 10 mol * 22.4 L / mol = 224 L.
Answer: the volume of sulfur (VI) oxide is 224 liters.
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