What mass is the precipitate formed when the solution containing 34 g of silver nitrate and the sodium chloride solution is poured?
The equation for the reaction of silver nitrate with sodium chloride:
AgNO3 + NaCl = AgCl + NaNO3
Amount of silver nitrate substance:
v (AgNO3) = m (AgNO3) / M (AgNO3) = 34/170 = 0.2 (mol).
According to the reaction equation, 1 mol of AgCl is formed per 1 mol of AgNO3, therefore:
v (AgCl) = v (AgNO3) = 0.2 (mol).
Thus, the mass of the precipitate of silver chloride formed is:
m (AgCl) = v (AgCl) * M (AgCl) = 0.2 * 143.5 = 28.7 (g).
Answer: 28.7 (d).
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.