# What mass of 78% sulfuric acid solution is required to obtain ammonium sulfate from 102 kg

**What mass of 78% sulfuric acid solution is required to obtain ammonium sulfate from 102 kg of ammonia, if the reaction yield is 98% of the theoretically possible?**

Ammonia reacts with sulfuric acid. This synthesizes the ammonium sulfate salt.

This reaction proceeds according to the following chemical reaction equation:

2NH3 + H2SO4 = (NH4) 2SO4;

Let’s calculate the chemical amount of ammonia. For this purpose, we divide its weight by its molar mass.

M NH3 = 14 + 3 = 17 grams / mol;

N NH3 = 102,000/17 = 6,000 mol;

With this amount of ammonia, 6000/2 = 3000 mol of sulfuric acid will react.

Let’s calculate its weight.

To do this, we multiply the chemical (molar) amount of a substance by its molar (atomic) mass.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

The weight of sulfuric acid will be:

m H2SO4 = 3000 x 98 = 294,000 grams;

The weight of the initial sulfuric acid solution will be 294,000 / 0.78 / 0.98 = 384 615 grams = 384.6 kg;