What mass of a 25% sulfuric acid solution must be taken to dissolve 8.4 g of iron in it?

We draw up an equation for the reaction and place the coefficients: H2SO4 + Fe = FeSO4 + H2.
When sulfuric acid and iron interact, ferrous sulfate is formed and hydrogen is released.
1) Molar mass of iron: 56.
2) Find the amount of iron substance: 8.4 / 56 = 0.15 mol.
3) According to the reaction equation, one mole of iron accounts for one mole of sulfuric acid. This means that the amount of sulfuric acid substance is 0.15 mol.
4) Molar mass of sulfuric acid: 0.15 * (2 + 32 + 64) = 0.15 * 98 = 14.7 g.
5) Find the mass of the sulfuric acid solution. To do this, we multiply the mass of the solute by one hundred percent and divide by the mass fraction of the substance: 14.7 * 100/25 = 58.8 g.
Answer: The mass of the sulfuric acid solution is 58.8 g.

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