What mass of benzene can be obtained from 67.2 liters of acetylene if the yield is 75% of the theoretical?
July 29, 2021 | education|
Let’s execute the solution:
According to the condition of the problem, we write down the equation of the process:
2C2H2 = C6H6 – trimerization, benzene was formed;
M (C6H6) = 78 g / mol;
M (C2H2) = 26 g / mol.
1 mol of gas at normal level – 22.4 liters;
X mol (C2H2) -67.2 liters from here, X mol (C2H2) = 1 * 67.2 / 22.4 = 3 mol;
3 mol (C2H2) – X mol (C6H6);
-3 mol -1 mol from here, X mol (C6H6) = 3 * 1/3 = 1 mol.
We find the mass of the product, taking into account its yield:
m (C6H6) = Y * M = 1 * 78 = 78 g (theoretical weight);
m (C6H6) = 0.75 * 78 = 58.5 g
Answer: benzene weighing 58.5 g was obtained
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