What mass of bromine is required for the reaction with 23 g of ethylene?

1. Let’s write down the reaction equation:

C2H4 + Br2 = C2H4Br2.

2. Find the amount of ethylene:

n (C2H4) = m (C2H4) / M (C2H4) = 23 g / 28 g / mol = 0.82 mol.

3. Using the reaction equation, we find the amount and then the mass of bromine:

n (Br2) = n (C2H4) = 0.82 mol.

m (Br2) = n (Br2) * M (Br2) = 0.82 mol * 160 g / mol = 131.43 g.

Answer: m (Br2) = 131.43 g.

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