What mass of calcium oxide is obtained by decomposition of 10 kg of limestone, if the yield is 90%

What mass of calcium oxide is obtained by decomposition of 10 kg of limestone, if the yield is 90% of the theoretically possible?

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

This also synthesizes 1 mol of calcium oxide

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 10,000 / 100 = 100 mol;

During the reaction, 100 x 0.9 = 90 mol of calcium oxide will be synthesized.

N CaO = 90 mol;

Its weight will be:

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 90 = 5,040 grams = 5.04 kg;




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