# What mass of methane will be obtained by fusing 120 grams of CH3COONa

What mass of methane will be obtained by fusing 120 grams of CH3COONa (sodium acetate) with alkali, if the mass fraction of methane yield is 95%?

Let’s implement the solution:

According to the condition of the problem, we write down the equation of the process:
CH3COONa + NaOH = CH4 + Na2CO3 – exchange, methane was obtained;

Calculations:
M (CH3COONa) = 81.9 g / mol;

M (CH4) = 16 g / mol;

Y (CH3COONa) = m / M = 120 / 81.9 = 1.46 mol;

Y (CH4) = 1.46 mol so the amount of substances is 1 mol.

Find the mass of the product:
m (CH4) = Y * M = 1.46 * 16 = 23.36 g (theoretical weight);

m (CH4) = 0.95 * 23.36 = 22.19 g (practical weight).

Answer: the mass of methane is 22.19 g

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