What mass of potassium sulfate is formed by the interaction of 49 g of sulfuric acid with potassium hydroxide?

Reaction equation: 2KOH + H2SO4 = K2SO4 + 2H2O
According to the periodic table, we determine the molar mass of sulfuric acid M = 1 * 2 + 32 + 16 * 4 = 98 g / mol. And the molar mass of potassium sulfate M = 39 * 2 + 32 + 16 * 4 = 174 g / mol. Let’s find the amount of sulfuric acid substance: n = m / M = 49 g / 98 g / mol = 0.5 mol. According to the reaction from 1 mol of acid, 1 mol of potassium sulfate is obtained, n (H2SO4) = n (K2SO4) = 0.5 mol. Find the mass of potassium sulfate: m = n * M = 0.5 mol * 174 g / mol = 87 g.
Answer: the mass of potassium sulfate is 87 g.