What mass of sodium oxide is required to react with 105 g of 60% nitric acid solution?

1. The reaction takes place according to the equation:

Na2O + 2HNO3 = NaNO3 + H2O;

2.m (HNO3) = m (HNO3 solution) * w (HNO3) (in fractions);

m (HNO3) = 105 * 0.6 = 63 g;

3. M (HNO3) = 1 + 14 + 3 * 16 = 63 g / mol;

n (HNO3) = m (HNO3): M (HNO3);

n (HNO3) = 63: 63 = 1 mol;

4.According to the reaction equation, the acid requires twice as much as sodium oxide, then the amount of oxide:

n (Na2O) = n (HNO3): 2 = 1: 2 = 0.5 mol;

5.m (Na2O) = n (Na2O) * M (Na2O);

M (Na2O) = 2 * 23 + 16 = 62 g / mol

m (Na2O) = 0.5 * 62 = 31 g.

Answer: 31 g.