What mass of sulfate will be obtained when 70 g of zinc containing 5% impurities are dissolved in sulfuric acid? how much hydrogen will be released in this case.
The chemical reaction of zinc with sulfuric acid proceeds according to the following scheme:
Zn + H2SO4 → ZnSO4 + H2;
Substances interact in equimolar amounts.
Let’s determine the molar amount of zinc.
M Zn = 65 grams / mol;
N Zn = 70 x 0.95 / 65 = 1.023 mol;
Therefore, during the reaction, 1.023 mol of hydrogen will be synthesized.
Let us find the volume of synthesized gas, knowing the volume of 1 mole of gas:
V H2 = 22.4 x 1.023 = 22.915 liters;
Let’s calculate the weight of the synthesized 1.023 mol of zinc sulfate.
M ZnSO4 = 65 + 32 + 16 x 4 = 161 grams / mol;
m ZnSO4 = 1.023 x 161 = 164.7 grams;
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